In a reaction vessel 0.184 g of NaOH is required to be added for completing the reaction. How many millilitre of 0.150 M NaOH solution should be added for this requirement?
Molar mass of NaOH = 40 g mol-1
1000 mL of NaOH solution contains 0.150 mol = 0.150 x 40 = 6 g
It means that 6g sodium hydroxide is present in 1000 mL
0.184 g sodium hydroxide would be present in
What volume of 9M HCl and 4 MHCl should be mixed to get 1L of 5M HCl solution?
Volume of 4 M HCl required = (1 - x) litre
How many moles of NaOH are contained in 27mL of 0.15 M NaOH?
1000mL of NaOH contains 0.15 moles
27 mL of NaOH contains 
= 0.004 moles
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